Question

Area of trapezium ABCD=57 cmBC=7cmAD=12cmcaculate the height

Answer 1

Given,
ABCD is a trapezium
Ar.(trap. ABCD) = 57 cm²
AD = 12 cm
BC = 7 cm
So,
Ar.(trap. ABCD) = 1/2*(AD+BC)*h
57*2= (12+7)h
114= 21h
38= 7h
h= 38/7= 5.428...= 5.43 cm (approx)

Hope this helps you!