Question

AREA OF TRIANGLE FORMED BY THE POINTS (2,5) (-3,4) AND (7,-1) IN SQUARE UNIT IS
A.35
B.35/2
C.15
D.0

Answer 1

Use this formula= 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

you will sure get the answer

Answer 2

To find area of the triangle:-

we have to apply the formula
i.e. 1/2 {x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}

$\frac{1}{2} (2( 4 - ( - 1)) + ( - 3)( - 1 - 5) + 7(5 - 4))$
$\frac{1}{2} (2(5) - 3( - 6) + 7(1))$
$\frac{1}{2} (10 + 18 + 7)$
$\frac{1}{2} \times 35$
$\frac{35}{2}$


So your answer is B.35/2

HOPE THIS HELPS U.......❤