Math, asked by satyajitbiswaljune, 6 months ago

logx (2)=0.1412 find logx (1600)

Answers

Answered by YUVILOVE2009

13

Answer:

: 4^((log_2logx))=logx-(logx)^2+1 (base is e)

Missing: 0.1412 ‎(1600)

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