Area of triangle in given figure
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54 cm²
Firstly join A and P point.
Step-by-step explanation:
Here, we get two triangles
∆ APB and ∆ APC
In ∆ APB,
Area = 1/2 × 10 × 6
∆APB area = 30 cm²
In ∆ APC,
Area = 1/2 × 16× 3
∆ APC area = 24cm².
Total area of ∆ ABC =∆APB + ∆APC
= 30 cm²+ 24 cm²
= 54 cm²
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