area of triangle is 18sq.uints vertics are (3,4)(-3,-2)(p,-1) find the value of "p"
Answers
Answered by
2
for this use the formula of area of triangle of coordinate geometry
chirag150:
plz once u do full sum and so me na
ok i vl send the pic
Answered by
2
Area of triangle =18 cm²
1/2[3(-2--1)+-3(-1-4)+p(4--2)] =18
on going 2 of 1/2 in R. H.S so 18×2=36
[3(-1)-3(-5)+p(6)=18
-3+15+6p=18
12+6p=18
6p=18-12
6p=6
p=1
1/2[3(-2--1)+-3(-1-4)+p(4--2)] =18
on going 2 of 1/2 in R. H.S so 18×2=36
[3(-1)-3(-5)+p(6)=18
-3+15+6p=18
12+6p=18
6p=18-12
6p=6
p=1
its fine hehee
ok
p=4or-8
yes
I will ask one more question
kk
yes
send fast
don't worry send I will answer your question
send fast
Similar questions