area of triangle whose vertices are A(0,0) , B(3, 1) C(2, 4) is
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Area of ∆ ABC is 5 sq-units.
Given:
- A ∆ABC, with vertices A(0,0) , B(3, 1), C(2, 4).
To find:
- Find area of ∆ ABC.
Solution:
Formula to be used:
If , ,and are the vertices of triangle then it's area is given by
Step 1:
Write the coordinates of given vertices.
A(x1,y1)=A(0,0)
B(x2,y2)=B(3,1)
and C(x3,y3)= C(2,4)
Step 2:
Put the values in the formula.
or
or
or
Ar.(∆ ABC)= 5 sq-units.
Thus,
Area of ∆ ABC is 5 sq-units.
Learn more:
1) Find the area of the triangle whose vertices are (1,0),(6,0)and(4,3)
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