Question

Area of tripazium is 28cm².Height is 4 cm & one of parellel side is 6cm , find other parellel side . Answer is 8cm .. Pls tell me process of taking out the answer .. Irrelevant question will be reported​

Answer 1

Area of trapezium = 28 cm²

Height of the trapezium = 4 cm

One of the parallel sides of trapezium = 6 cm

To find = Measurement of another parallel side

We know,

Area of trapezium = ½ × {Sum of parallel sides} × {Height of trapezium}

$\tt \to28 = \frac{1}{2} \{ 6 + unknown \: \: sides\} \times 4 \\ \\ \tt \to \frac{28}{ \frac{1}{2} } = \{ 6 + unknown \: \: sides\} \times 4 \\ \\ \tt \to \frac{28}{ \frac{1}{2} \times 4} = 6 + unknown \: \: sides \\ \\ \sf \to \: unknown \: \: sides = \frac{28}{ \frac{1}{2} \times 4} - 6 \\ \\ \sf \to \: unknown \: \: sides = \frac{28}{2} - 6 \\ \\ \sf \to \: unknown \: \: sides = 14 - 6 \\ \\ \sf \to \: unknown \: \: sides = \red8 \: cm$

Answer 2

Step-by-step explanation:

Area of trapezium = 28 cm²

Height of the trapezium = 4 cm

One of the parallel sides of trapezium = 6 cm

To find = Measurement of another parallel side

We know,

Area of trapezium = ½ × {Sum of parallel sides} × {Height of trapezium}

\begin{gathered} \tt \to28 = \frac{1}{2} \{ 6 + unknown \: \: sides\} \times 4 \\ \\ \tt \to \frac{28}{ \frac{1}{2} } = \{ 6 + unknown \: \: sides\} \times 4 \\ \\ \tt \to \frac{28}{ \frac{1}{2} \times 4} = 6 + unknown \: \: sides \\ \\ \sf \to \: unknown \: \: sides = \frac{28}{ \frac{1}{2} \times 4} - 6 \\ \\ \sf \to \: unknown \: \: sides = \frac{28}{2} - 6 \\ \\ \sf \to \: unknown \: \: sides = 14 - 6 \\ \\ \sf \to \: unknown \: \: sides = \red8 \: cm\end{gathered}

→28=

2

1

{6+unknownsides}×4

→

2

1

28

={6+unknownsides}×4

→

2

1

×4

28

=6+unknownsides

→unknownsides=

2

1

×4

28

−6

→unknownsides=

2

28

−6

→unknownsides=14−6

→unknownsides=8cm