area of two circles are in ratio 16 :81 find ratio of their circumference
Answers
Answered by
10
area of circle = π r²
Let the radius of first circle is r units
and the radius of second circle be R units
area of first circle = πr²
area of second circle = πR²
A/q
(πr²)/(πR²) = 16/81
⇒r²/R² = 16/81
⇒r/R = 4/9______(1)
now, circumference of first circle = 2πr
circumference of second circle = 2πR
ratio, (2πr)/(2πR) =r/R = 4/9_______(from equation 1)
Let the radius of first circle is r units
and the radius of second circle be R units
area of first circle = πr²
area of second circle = πR²
A/q
(πr²)/(πR²) = 16/81
⇒r²/R² = 16/81
⇒r/R = 4/9______(1)
now, circumference of first circle = 2πr
circumference of second circle = 2πR
ratio, (2πr)/(2πR) =r/R = 4/9_______(from equation 1)
Answered by
2
Area of two circles = 16 : 81
ie pi * r1^2 : pi * r2^2 = 16:81
r1^2 : r2^2 = 4^2 : 9^2
r1 : r2 = 4 : 9
Circumference = 2*pi*r1 : 2*pi*r2
= r1 : r2
= 4 : 9
ie pi * r1^2 : pi * r2^2 = 16:81
r1^2 : r2^2 = 4^2 : 9^2
r1 : r2 = 4 : 9
Circumference = 2*pi*r1 : 2*pi*r2
= r1 : r2
= 4 : 9
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