Question

AREA OF TWO SIMILAR TRIANGLES ARE 225 sq.cm. AND81sq.cm. IF A SIDE OF A SMALLER TRIANGLE IS 12 CM. THEN FIND CORRESPONDING SIDE OF THE BIGGER TRIANGLE.​

Answer 1

Answer:

Step-by-step explanation:

given :

• AREA OF TWO SIMILAR TRIANGLES ARE 225 sq.cm. AND81sq.cm. IF A SIDE OF A SMALLER TRIANGLE IS 12 CM. THEN FIND CORRESPONDING SIDE OF THE BIGGER TRIANGLE.

to find :

• SIDE OF THE BIGGER TRIANGLE.

solution :

• x= 12x √225/81 = 12× 15/9

• = 20 cm

Answer 2

Answer:

• 20 cm is the required answer .

Step-by-step explanation:

According to the Question

It is given that,

• Area of ∆ ,A1 = 225 cm²
• Area of ∆, A2 = 81 cm²
• Side of smaller triangle ,S2 = 12cm

Let , the side of bigger triangle be S1 cm.

Now, according to the Theorem

The ratio of the area of two similar triangles are equal to the ratio of square of any two corresponding sides.

Area of ∆A1/Area of ∆A2 = (S1/12)²

By putting the value we get

➻ 225/81 = (S1/12)²

➻ √225/81 = S1/12

➻ 15/9 = S1/12

➻ 15×12/9 = S1

➻ S1 = 180/9

➻ S1 = 20cm

• Hence, the side of bigger triangle is 20cm.