Question

Area of two similar triangles are in the ratio 9:16 .Sides of the triangles are in the ratio-
a. 4:3
b. 3:4
c. 81:256
d. 2:3​

Answer 1

Answer:

81:256

Step-by-step explanation:

Let ∆ABC (whose sides are a,b and c)and ∆ PQR (whose sides are p,q and r) are

two similar triangles , therefore

a/p = b/q = c/r = k(let) . , thus , a=pk , b=qk. and c=rk.

Given that:-

(a+b+c)/(p+q+r)=9/16. , ( putting a=pk , b=qk and c= rk.)

or. k.(p+q+r)/(p+q+r)= 9/16.

or. k=9/16.

Area of ∆ABC/Area of ∆PQR = (a/p)^2=(b/q)^2=(c/r)^2=k^2.

= (9/16)^2.

=81/256. or. 81 : 256. , Answer.

Answer 2

Answer:

The perimeters of similar triangles are in same proportion as their corresponding sides. hence the answer is A