Question

area under velocity time curve of a particle starting with a velocity of 2 metre per second travelling with uniform acceleration for 8 second is 80 metre per second square calculate the final velocity​

Answer 1

Answer:

v = 642 m / sec

Explanation:

Given :

Initial velocity ( u ) = 2 m / sec

Acceleration ( a ) = 80 $m/sec^2$

Time ( t ) = 8 sec

We have find final velocity ( v )

we have

v = u + a t

where

v = final velocity

u = initial velocity

a = acceleration  

t = time

put the value here we get

v = 2 + 80 × 8

v = 2 + 640

v = 642 m / sec

Thus we get final velocity​ of particle .

Answer 2

Answer :-

v = 642 m/s

Given :-

u = 2 m/s

t = 8 s

a = 80 m/s²

To find :-

It's final velocity .

Solution:-

Let it's final velocity be v.

Velocity :- The rate of change of displacement is known as velocity.

• The slope of displacement- time graph gives velocity.

As we know the velocity of the particle is given by first equation of motion.

From first equation of motion:-

$\huge \boxed{v = u +at}$

where a is acceleration

t is time and u is initial velocity.

Put the given value ,

→$v = u + at$

→$v = 2 + 80 \times 8$

→$v = 2 + 640$

→$v = 642 m/s$

hence,

The final velocity of the particle will be 642 m/s.