area under velocity time curve of a particle starting with a velocity of 2 metre per second travelling with uniform acceleration for 8 second is 80 metre per second square calculate the final velocity
Answers
Answer:
v = 642 m / sec
Explanation:
Given :
Initial velocity ( u ) = 2 m / sec
Acceleration ( a ) = 80
Time ( t ) = 8 sec
We have find final velocity ( v )
we have
v = u + a t
where
v = final velocity
u = initial velocity
a = acceleration
t = time
put the value here we get
v = 2 + 80 × 8
v = 2 + 640
v = 642 m / sec
Thus we get final velocity of particle .
Answer :-
v = 642 m/s
Given :-
u = 2 m/s
t = 8 s
a = 80 m/s²
To find :-
It's final velocity .
Solution:-
Let it's final velocity be v.
Velocity :- The rate of change of displacement is known as velocity.
- The slope of displacement- time graph gives velocity.
As we know the velocity of the particle is given by first equation of motion.
From first equation of motion:-
where a is acceleration
t is time and u is initial velocity.
Put the given value ,
→
→
→
→
hence,
The final velocity of the particle will be 642 m/s.