areas of two similar triangle are 338sq.cm and 200sq.cm. Find the ratios of their corresponding sides
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Hi there,
Acc to the theorem,
The ratios of the areas of two similar triangles is equal to the square of their corresponding sides..
so,
Let area of T1=338sq.cm
Let area of T2=200sq.cm
then, T1/T2=(side of T1)^2/(side of T2)^2
so putting the known we get the ratio sidesas
side of T1/side of T2=sqrt(338)/sqrt(200)=18.38/14.14
Hence the ratio is
18.38 : 14.14
Hope it helps...
pls make it the brainliest
Acc to the theorem,
The ratios of the areas of two similar triangles is equal to the square of their corresponding sides..
so,
Let area of T1=338sq.cm
Let area of T2=200sq.cm
then, T1/T2=(side of T1)^2/(side of T2)^2
so putting the known we get the ratio sidesas
side of T1/side of T2=sqrt(338)/sqrt(200)=18.38/14.14
Hence the ratio is
18.38 : 14.14
Hope it helps...
pls make it the brainliest
mrigansh:
why did you report my ans
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