Question

areas of two similar triangle are in respectively 9cm square and 16cm square find ratio of their corresponding sides​

Answer 1

$area \: of \: triangle = 9 {cm}^{2} \\ \frac{1}{2} bh = 9 \\ b = \frac{18}{h} \\ \\ \\ \\ \\ \\ \\ area \: of \: triangle = \frac{1}{2}bh = 16 {cm}^{2} \\ b = \frac{32}{h}$

Now,

$Required \: Ratio = \frac{18}{h} \div \frac{32}{h} \\ \frac{18}{32} = \frac{9}{16} \: \: \: \: \: \: or \: \: 9:16$