Question

Areas of two similar triangles are 81:10 then the ratio of corresponding sides is

Answer 1

this is the amswer of your question. so the ratio of corrosponding sides is 9:3.1622

Answer 2

$\huge \bf{ \red{hey}}$

$\huge{ \mathfrak{ \pink{here \: is \: answer}}}$

$\bf{question = }$
Areas of two similar triangles are 81:10 then the ratio of corresponding sides is


Now

$\bf{solution - }$
$\sf{given - }$
Areas of two similar triangles are 81:10.

$\sf{to \: find - }$


the ratio of corresponding sides?


$\bf{ \green{step \: by \: step \: explanation}}$

As we are familiar with a theorem that

let ABC and PQR be two similar triangles.

and

AB is corresponding side of PQ
AC is corresponding side of PR
and
BC is corresponding side of QR

then
$\frac{ar \triangle{abc}}{ar \triangle{pqr}} = (\frac{ab}{pq} )^{2} = (\frac{ac}{pr}) ^{2} = (\frac{bc}{qr} )^{2}$
hence

we are given the ratio of areas then

$\frac{81}{10} = (\frac{ab}{pq} )^{2}$

so

$\frac{ab}{pq} = \sqrt{ \frac{81}{10} }$

$\frac{ab}{pq} = \frac{9}{2 \sqrt{5} }$

and

we already showed above that ratios of sides are equal


so

answer is

$\bf{ \frac{ab}{pq} = \frac{9}{2 \sqrt{5}} }$

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$\huge{ \purple{thanks}}$


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