Question

Arectangular plot is 90 m long and 60 m wide. Two roads of 1 m each are running parallel to width of
plot and one road of 1 mis running parallel to the length of the plot. Find the area covered by the roads
(a) 216 m
(b) 225 m
(c) 208 m
(d) 245 m
In the given parallelogram ABCD, AE = FC = 11 cm and
A​

Answer 1

Answer:

as 1 m is added to both length and breadth of yhe rectangle so the new length and breadth of the new rectangle will be 91 and 61 resp.

now area with roads = 91×61 = 5551 sq.m

and without roads area is 90×60 = 5400 sq.m

so the difference = 151 sq m tells us the area of the roads .

Step-by-step explanation:

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Answer 2

Answer:c) 208 m

Step-by-step explanation: area of roads = area of 2 roads parallel to width+ area of road parallel to lenth - common area of 3 roads

=2*1*60+ 1*90- 1*1-1*1

=120+90-2

=208

(The third road passes through the two roads so we will subtract the common area)