Argon is stored in a reservoir at 500K. Determine the speed of sound in it (up-to 2 decimal points). (Take γ=1.4 and Molecular Weight of Argon: 39.94)
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Given : Temperature = 500K, γ = 1.4 and Molecular Weight of Argon = 39.94
To find : The speed of sound in it
Solution : We know that, speed of sound is given by formula
• V = √γRT/M
V = √1.4×8.314×500/39.94 m/s
= √ 145.7135
• V = 12.07118
Upto two decimals, V = 12.07
• So, The speed of sound in it is 12.07
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