Question

Ariel is 3 years younger than Bob. The sum of their ages is 53. How old were they 7 years ago?

Answer 1

Step-by-step explanation:

let the present years of Bob be x years and Ariel be x - 3 yrs.

A/ Q

x-3+ x= 53

2x-3=53

2×=53 +3

2x=56

x=56/2

x=28

present age of Bob= 28 yrs

present age of Ariel = 28 -3 = 25 yrs

their sum = 28 +25 = 53 yRs

therefore verified.

age of Ariel7 years ago = 25 -7 = 18 yrs

age of Bob 7 years ago = 28 - 7 = 21 yrs.

hope it helps you.....

Answer 2

Let Bob's age be x and Ariel's age be(x-3) years.

Sum of their ages = 53 years.

So, = x+x-3 = 53

= 2x-3=53

= 2x = 53+3

= 2x = 56

= x= 56/2 = x= 28 years

So, Bob's age = x= 28 years

Ariel's age = x-3 = 28-3 = 25 years

Their ages 7 years ago

Bob = 28-7 = 21 years

Ariel = 25-7 = 18 years.........

Mark it as brainliest......