Question

arithmetic mean of a observation was
Calculated as 45. in doing
so an observation was wrongly
taken as 42 for 24 what
would then be the correct
mean?
​

Answer 1

$\underline{\rule{287}{3}}$

CORRECT QUESTION :-

Arithmetic mean of 9 observations was calculated as 45. In doing so an observation was wrongly taken as 42 for 24. What would then be the correct mean?

$\underline{\rule{287}{3}}$

$\underline{\rule{287}{3}}$

SOLUTION :-

Given :-

• Arithmetic mean of 9 observations was calculated as 45.

• An observation was wrongly  taken as 42 instead of 24.

To find :-

The correct mean of the 9 observations.

Concept used :-

$\displaystyle{\tt{Arithmetic\ mean=\frac{Sum\ of\ all\ the\ observations}{Number\ of\ observations} }}$

Calculation :-

According to the question,

$\displaystyle{\tt{45=\frac{Sum\ of\ all\ the\ observations}{9} }}\\\\\displaystyle{\tt{\implies Sum\ of\ all\ the\ observations=45\times9 }}\\\\\boxed{\displaystyle{\tt{\implies Sum\ of\ all\ the\ observations=405 }}}$

Now an observation was wrongly taken as 42 for 24.

⇒42 - 24 = 18

So, 18 was added by mistakenly to the sum of the observations.

Now,

Sum of all the observations = 405 - 18 = 387

Again,

$\displaystyle{\tt{Arithmetic\ mean=\frac{387}{9} }}\\\\\boxed{\underline{\boxed{\displaystyle{\tt{\implies Arithmetic\ mean=43 }}}}}$

∴ So, the correct mean for the 9 observations is 43.

$\underline{\rule{287}{3}}$

Answer 2

Answer:

hmmm so answer is 43

Step-by-step explanation:

i nit give explain