arithmetic mean of first n natural numbers
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Let S be the required sum.
Therefore, S=1+2+3+4+5+.........+n
Clearly, it is an Arithmetic Progression whose first term = 1, last term = n and number of terms = n.
Therefore, S = n/2 (n + 1),
[Using the formula S = n/2(a + l)]
Therefore, S=1+2+3+4+5+.........+n
Clearly, it is an Arithmetic Progression whose first term = 1, last term = n and number of terms = n.
Therefore, S = n/2 (n + 1),
[Using the formula S = n/2(a + l)]
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