Question

Arithmetic progression 1/3,4/3,7/3,10/3.... Find the next two terms

Answer 1

The next two terms of A.P are $\frac{13}{3} \ and \ \frac{16}{3}$.

Step-by-step explanation:

$\frac{1}{3}, \frac{4}{3}, \frac{7}{3}, \frac{10}{3},......$

1st term = a = $\frac{1}{3}$

Common difference = d = $\frac{4}{3} - \frac{1}{3}$ = 1

Next two terms = $\frac{10}{3} + 1 = \frac{13}{3} \ and \ \frac{13}{3} + 1 = \frac{16}{3}$

Hence, the next two terms of A.P are $\frac{13}{3} \ and \ \frac{16}{3}$.