If p=4,q=-3,r= 2 find value of : p^3+q^3-r^3-3pqr3
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The value of p³ + q - r³ - 3pqr³ is 101.
Step-by-step explanation:
If p = 4, q = -3, r = 2
p³ + q³ - r³ - 3pqr³
= (4)³ + (-3)³ - (2)³ - 3(4)(-3)(2)
= 64 - 27 - 8 + 72
= 101
Hence, the value of p³ + q - r³ - 3pqr³ is 101.
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