Question

If p=4,q=-3,r= 2 find value of : p^3+q^3-r^3-3pqr3

Answer 1

The value of p³ + q - r³ - 3pqr³ is 101.

Step-by-step explanation:

If p = 4, q = -3, r = 2

p³ + q³ - r³ - 3pqr³

= (4)³ + (-3)³ - (2)³ - 3(4)(-3)(2)

= 64 - 27 - 8 + 72

= 101

Hence, the value of p³ + q - r³ - 3pqr³ is 101.