Math, asked by vvel237, 9 months ago

Arjun is twice as old as adhith .five years age Arjun's age was three times adhith's age

Answers

Answered by Anonymous
0

Answer:

let Aditya age be , x

then, Arjun age be , 2x

five year ago Aditya age = x-5

five year ago Arjun age = 2x-5

= 3(x-5 ) = 2x-5

= 3x-15 = 2x-5

= 3x + 2x = -5 + 15

= 5x = 10

= x= 2

then Aditya age = x+5 = 2+5 = 7 years

Arjun age = 2x+5 = 2X2+5 = 9 years

Answered by hridayeshdas2007
0

let Aditya age be , x

then, Arjun age be , 2x

five year ago Aditya age = x-5

five year ago Arjun age = 2x-5

= 3(x-5 ) = 2x-5

= 3x-15 = 2x-5

= 3x + 2x = -5 + 15

= 5x = 10

= x= 2

then Aditya age is

x+5 = 2+5 = 7 years

Arjun age is

2x+5 = 2X2+5 = 9 years

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