Math, asked by vansharya1010, 9 months ago

Arjun is twice as old as Shreya. Five years ago his age was three times Shreya’s age. Find their present ages.

Answers

Answered by pandeynishant013
2

Step-by-step explanation:

let the,

age of Shreya be x year

the age of Arjun be 2x year

Five years ago,

the age of Shreya=(x_5)years

the age of Arjun=(2x_5)years

According to question,

2x_5 =3(x_5)

= 2x_5=3x_15

=2x_3x=_15+5

=_x=_10

=x=10 years

Hence, Age of Shreya=x=10years

Age of Arjun=2x=2×10=20years

Answered by akshatkulhar09
0

Answer:

Step-by-step explanation:

let the,

age of Shreya be x year

the age of Arjun be 2x year

Five years ago,

the age of Shreya=(x_5)years

the age of Arjun=(2x_5)years

According to question,

2x_5 =3(x_5)

= 2x_5=3x_15

=2x_3x=_15+5

=_x=_10

=x=10 years

Hence, Age of Shreya=x=10years

Age of Arjun=2x=2×10=20years

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