Math, asked by vansharya1010, 10 months ago

Arjun is twice as old as Shreya. Five years ago his age was three times Shreya’s age. Find their present ages.

Answers

Answered by pandeynishant013
2

Step-by-step explanation:

let the,

age of Shreya be x year

the age of Arjun be 2x year

Five years ago,

the age of Shreya=(x_5)years

the age of Arjun=(2x_5)years

According to question,

2x_5 =3(x_5)

= 2x_5=3x_15

=2x_3x=_15+5

=_x=_10

=x=10 years

Hence, Age of Shreya=x=10years

Age of Arjun=2x=2×10=20years

Answered by akshatkulhar09
0

Answer:

Step-by-step explanation:

let the,

age of Shreya be x year

the age of Arjun be 2x year

Five years ago,

the age of Shreya=(x_5)years

the age of Arjun=(2x_5)years

According to question,

2x_5 =3(x_5)

= 2x_5=3x_15

=2x_3x=_15+5

=_x=_10

=x=10 years

Hence, Age of Shreya=x=10years

Age of Arjun=2x=2×10=20years

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