Question

Solve the following systems of equations:
$3x -\frac{y+7}{11}+2=10$
$2y +\frac{x+11}{7}=10$

Answer 1

Given :  

3x - ( y + 7)/11 + 2 = 10  …………...( 1 )

2y + (x + 11)/7  = 10 …………...( 2 )

Substitution  method is used to solve this Linear pair of Equations:

 

From eq 1 :

[(11 × 3x - ( y + 7) + 2 × 11]/11 = 10  

33x - y - 7 + 22 = 10 × 11

33x - y + 15 = 110

33x - y = 110 - 15

33x - y = 95

-y = 95 - 33x

y = 33x - 95 ………….(3)  

 

From eq 2 :  

[(7 × 2y + (x + 11)]/7  = 10

14y + x + 11 = 7 × 10

14y + x + 11 = 70

14y + x = 70 - 11

14y + x = 59 ………..(4)

On Substituting the value of y from eq 3 in equation (4) we obtain :  

14y + x = 59

14(33x - 95) + x = 59

462x - 1330 + x = 59

463x = 59 + 1330

463x = 1389

x = 1389/463

x = 3

On putting x = 3 in eq 3 we get :  

y = 33x - 95  

y = 33 × 3 - 95

y = 99 - 95

y = 4

Hence, the value of the given system of equation is x = 3   and y = 4.

Hope this answer will help you…

 

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Answer 2

Answer:

Hope it helps you.......