Arjun is twice as old as shreya. Five years ago his age was three times shreya's age....Find There present age.
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let A= arjun age and S= shreya age
A=2*S
A-5=3*(S-5)
solve both equations simultaneously for A and S to get the ages.
A=2*S
A-5=3*(S-5)
solve both equations simultaneously for A and S to get the ages.
Answered by
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shreya's age- x
arjun's age- 3x
so now shreya's age is x+5 because five years have passed and similarly arjun's age is 3x+5.
in the question, it says his current age(3x+5) is equal to twice of shreya's age- 2(x+5)
3x+5 = 2(x+5)
3x+5 = 2x+10
3x -2x= 10-5
x=5
so,
shreya's present age(x+5)= 5+5=10 years old.
arjun's present age 2(x+5)= 2(5+5)
= 20 years old.
shreya's age- x
arjun's age- 3x
so now shreya's age is x+5 because five years have passed and similarly arjun's age is 3x+5.
in the question, it says his current age(3x+5) is equal to twice of shreya's age- 2(x+5)
3x+5 = 2(x+5)
3x+5 = 2x+10
3x -2x= 10-5
x=5
so,
shreya's present age(x+5)= 5+5=10 years old.
arjun's present age 2(x+5)= 2(5+5)
= 20 years old.
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