Question

Arjun is twice as old as shriya . five years ago his age was three times shriya’s age. Find their present ages

Answer 1

Let Arjun's present age be x

And shriya's present age be y.

Arjun is twice as old as shriya,

x = 2y

Five years ago,their ages:-

Arjun's age = x-5

Shriya's age = y - 5

five years ago his age was three times shriya’s age.

x-5 = 3(y-5)

x-5 = 3y-15

2y-5 = 3y-15

3y-2y = -5+15

y = 10

Therefore,

The present ages of

Arjun is 2(10) = 20 years

Shriya is 10 years

Hope it helps,..

Answer 2

solution:

$\footnotesize\texttt{Let us take shriya's age be x years. }$

$\footnotesize\texttt{then arjun's present age would be 2x years.}$

$\footnotesize\texttt{shriya's age five years ago was (x-5) years. }$

$\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }$

$\footnotesize\texttt{it is given that arjun's age five.}$

$\footnotesize\textsf{ year ago was three times shriya's age.}$

Thus,

➠$\small\mathtt{2x-5=3(x-5) }$

➠$\small\mathtt{2x-5=3x-15 }$

➠$\small\mathtt{15-5=3x-2x }$

➠$\small\mathtt{10= x }$

so,shriya's present age =x =10 Years .

therefore, arjun's present age =2x=2×10=20 years.