Arjun is twice as old as Shriya. Five years ago his age was three times Shriya’s age.
Find their present ages
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Answer:
let age of Arjun be
′
x
′
and age of Shriya be
′
y
′
then according to question x=2y−−−(1)
and five years ago
x−5=3(y−5)
x−5=3y−15
x−3y+10=0−−−(2)
using eq(1)
2y−3y+10=0
y=10
and x=20
∴ age of Arjun is 20 and age of Shriya is 10
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