Math, asked by dfuyiruogvjkjjgdgjxv, 3 months ago

Arjun is twice as old as shriya. Five years ago his age was three times Shriya's age.​

Answers

Answered by Anonymous
20

Correct question:-

\tt\longrightarrow{} Arjun is twice as old as Shriya. Five years ago his age was three times Shriya's age. Find their present ages.

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Given:-

Arjun is twice as old as Shriya.

Five years ago his age was three times Shriya's age.

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To find:-

Their present ages.

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Solution:-

★ Let us take Shriya's present age to be x years.

★ Then Arjun's present age would be 2x years.

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\star{\boxed{\sf{\orange{Shriya's\: age\: five\: years\: ago\: was (x - 5) years.}}}}

\star{\boxed{\sf{\purple{Arjun's\: age\: five\: years\: ago\: was (2x - 5) years.}}}}

※ It is given that Arjun's age five years ago was three times Shriya's age.

Thus,

\large{\tt{\longmapsto{2x - 5 = 3(x - 5)}}}

\large{\tt{\longmapsto{2x - 5 = 3x - 15}}}

\large{\tt{\longmapsto{15 - 5 = 3x - 2x}}}

\boxed{\large{\tt{\longmapsto{\red{10 = x}}}}}

So,

Shriya's present age:-

\large{\tt{\longmapsto{x = 10~ years.}}}

Therefore,

Arjun's present age:-

\large{\tt{\longmapsto{2x = 2 × 10 = 20~years.}}}

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Answered by charisma47
3

Answer:

Let Shriya′s present age is x years. Then, Arjun′s present age will be 2x years. Shriya′s present age is 10 years. Arjun′s present age is 20 years.

hope it helps you

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