Question

Four particles of masses 2 kg, 3 kg.
2 kg and 4 kg are at the corners of a
square of diagonal 4 m, as shown.
The net gravitational force on a
particle of mass 1 kg at the centre of
the square is​

Answer 1

Explanation:

Solution :

In Fig.

AC=BD=12+12−−−−−−√=2–√m

∴AO=BO=CO=DO=2–√2=12–√m

(i) About the axis passing through Oand⊥ to plane of square,

I=4(12–√)2+2(12–√)2+3(12–√)2+5(12–√)2

=14×12=7kgm2

(ii) About AB

I=4×(0)2+2(0)2+3(1)2+5(1)2=8kgm2

About diagonal BD

I=4(12–√)2+2(0)2+3(12–√)2+5(0)2

=3.5kgm2