Arjun is twice as old as Shriya. Five
years ago his age was three times
Shriya’s age. Find their present ages.
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let Shriya age = x yrs.
then Arjun's age = 2x yrs.
five years ago:-
Shriya's age = x - 5
Arjun's age = 2x - 5
A.T.Q
2x - 5 = 3(x-5)
2x-5 = 3x-15
2x-3x = -15+5
-1x = -10
x = -10/-1
x = 10
Shriya's age = x = 10 yrs.
Arjun's age = 2x = 2×10 = 20 yrs.
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