Math, asked by rishabjaral762, 11 months ago

Arjun is twice as old as shriya.Five years ago his age was three times shriya's age.Find their parents age.

Answers

Answered by harshit438
0

Answer:

Shriya's age=x

=5years

Arjun's age=2x

=10years

Step-by-step explanation:

Let Shriya's age be x

and Arjun's age be 2x

According to the question :-

2x+5=3x

5=3x-2x

5=x

Shriya's age=x

Shriya's age=x =5years

Shriya's age=x =5yearsArjun's age=2x

Shriya's age=x =5yearsArjun's age=2x =10years

Answered by BrainlySamaira
8

solution:

\footnotesize\texttt{Let us take shriya's age be x years. }

\footnotesize\texttt{then arjun's present age would be 2x years.}

\footnotesize\texttt{shriya's age five years ago was (x-5) years. }

\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }

\footnotesize\texttt{it is given that arjun's age five.}

\footnotesize\textsf{ year ago was three times shriya's age.}

Thus,

\small\mathtt{2x-5=3(x-5) }

\small\mathtt{2x-5=3x-15 }

\small\mathtt{15-5=3x-2x }

\small\mathtt{10= x }

➠so,shriya's present age =x =10 Years .

➠therefore, arjun's present age =2x=2×10=20 years.

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