Question

Army Technical
25
A stone thrown upwards with an initial velocity of 50 m/s. What is the maximum
height that the stone will reach?​

Answer 1

GiveN :-

• A stone thrown upwards with an initial velocity of 50 m/s.

To FinD:-

• The maximum height that the stone will reach.

SolutioN :-

Given that , a stone thrown upwards with an initial velocity of 50 m/s. We need to find the maximum height reached by the stone. So we know the formula of maximum height when a stone is thrown with a velocity u , then

$\red{\bigstar}\underline{\textsf{ Using the Formula of Maximum Height :- }}$

$\sf\dashrightarrow \pink{ Height_{(maximum)}=\dfrac{u^2}{2g} }\\\\\dashrightarrow \sf H_{(max)}= \dfrac{(50m/s)^2}{2(10 m/s^2)}\\\\\dashrightarrow \sf H_{(max)}= \dfrac{2500 m^2/s^2}{20m/s^2}\\\\\dashrightarrow \underset{\blue{\sf Required\ Height }}{\underbrace{ \boxed{\pink{\frak{ Height_{(maximum)}= 125 m }}}}}$