Question

Arrange following orbital in the increasing order of energy
i. n = 4,1 = 2, ml = -2, ms=-1/2
ii. n = 3,1 = 2, ml = 1, ms = +1/2
iii. n = 4,1 = 1, ml = 0, ms = +1/2
iv. 4. n = 3,1 = 2, ml =-2, ms =-1/2
v. n = 3,1 = 1, ml=-1,ms = +1/2
vi. n = 4,1 = 1, ml = 0, ms = +1/2

Answer 1

Answer:

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