Question

expand by using identities x+2y+4c

​

Answer 1

$\huge\bf\red{AnsWER}$

Step-by-step explanation:

$=>x+2y+4c$ (using identity $(a+b+c)^{2}$

$________-------________$

$=>x^{2}+(2y)^{2}+(4c)^{2} +2x×2y+2×2y×4c+2×4c×x \\=> x^{2}+4y^{2}+16c^{2}+2(2xy+8yc+4xc) \\=> x^{2}+2y^{2}+4c^{2}+4xy+16yc+8xc$

follow me..