Question

arrange in decreasing order ,the energy of 2S orbital in the following atom H,Na,Li,K​

Answer 1

The decreasing order of energy for 2s is: H > K > Na > Li

Answer 2

Given elements are arranged in decreasing 2s energy orbital as follows.

                   K < Na < Li < H

Explanation:

Atomic number of hydrogen is 1 and its electronic configuration is $1s^{1}$.

Atomic number of sodium is 11 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{1}$.

Atomic number of lithium is 3 and its electronic configuration is $1s^{2}2s^{1}$.

Atomic number of potassium is 19 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}$.

As hydrogen atom does not have a 2s orbital so it will not have any energy in that orbital. Therefore, given elements are arranged in decreasing 2s energy orbital as follows.

                   K < Na < Li < H

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