Question

Arrange in increasing order 3 root 7 ,4 root 11,6 root 50

Answer 1

Given numbers are 3√7, 4√11, 6√50

Main point: when a number present outside the root goes in, it would get squared and multiplied by the number inside the root

So, the numbers be √3²x7, √4²x11, √6²x50\
                            ⇒ √9x7, √16x11, √36x50
                            ⇒ √63 → 3√7, √176 → 4√11, √1800 → 6√50

Therefore, their increasing order be 3√7, 4√11, 6√50

Answer 2

Hi

The given numbers are 3✓7, 4✓11, 6✓50.

As we know when a number present outside of root goes in,it would get squared and multiplied with the number that is present inside the root.

Thus for 3✓7 the number is ✓3^2×7=>✓9×7=>✓63.

For 4✓11 the number is ✓4^2×11=>✓16×11=>✓176.

For 6✓50 the number is ✓6^2×50=>✓36×50=>✓1800.

Therfore,their increasing order is 3✓7, 4✓11, 6✓50.

Hope it helps.