Arrange the data and prepare frequency osumbution table snally manamuou.
Qil. The perimeter of a rectangle and a square are same. The length and breadth of the rectangle are 30
cm and 14 em espectively. Find which figure has a greater are and by how much?
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Answer:
The perimeter of rectangle and square are equal.
The length of rectangle = 30 cm
The breadth of rectangle = 14 cm
The perimeter of rectangle = 2(l+b) = 2(30+14) = 2×44 = 88 cm
The perimeter of square = 4×side
88 cm = 4× side
88/4 = side
22 = side
Side of square = 22 cm
Area of rectangle = lb = 30×14 = 420 cm²
Area of square = side² = 22² = 484 cm²
484 cm² > 420 cm²
Area of square > Area of rectangle
So, Area of square - Area of rectangle
484 cm² - 420 cm² = 64 cm²
.°. The square has greater area by 64 cm².
I hope it results to be helpful...
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