Arrange the following compounds in the increasing order of their boiling points.
dimethyl ether, ethyl alcohol, propane, acetaldehyde.
Answers
Answered by
31
For any question...just learn the series...
Acid>alcohol>aldehyde>ketone>ether>hydrocarbon
Using this...
Ethyl alcohol > acetaldehyde > propanone > dimethyl ether
@skb
Answered by
11
Hello dear,
◆ Answer -
Increasing order of their boiling points for given options is -
Propane < Dimethyl ether < Acetaldehyde < Ethyl alcohol
● Explanation -
- All these given compounds have comparable molecular masses, so their boiling boints are influenced by type of intermolecular forces present in them.
- As Ethanol shows H-bonding, it have highest boiling point.
- As dipole-dipole interaction is more fierce in acetaldehyde than dimethyl ether, acetaldehyde will have higher boiling point.
- Propane having only van-der walls forces, it would have least boiling point.
Hope this helped you. Thanks for asking..
◆ Answer -
Increasing order of their boiling points for given options is -
Propane < Dimethyl ether < Acetaldehyde < Ethyl alcohol
● Explanation -
- All these given compounds have comparable molecular masses, so their boiling boints are influenced by type of intermolecular forces present in them.
- As Ethanol shows H-bonding, it have highest boiling point.
- As dipole-dipole interaction is more fierce in acetaldehyde than dimethyl ether, acetaldehyde will have higher boiling point.
- Propane having only van-der walls forces, it would have least boiling point.
Hope this helped you. Thanks for asking..
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