Question

Arrange the following equations in its standard form and
find a, b and c:
(1) 2x = 3y -5 (2) y = x + 3​

Answer 1

Answer:

a 2x , B 3y , C -5

Step-by-step explanation:

2x =3y -5

2x=2y

2(x+y)

Answer 2

Step-by-step explanation:

$(1) \: \: \: \: \: \: \: \: 2x = 3y - 5 \\ transpose \: 3y \: to \: left \: hand \: side \\ equation \: becomes \: 2x - 3y = - 5 \\ now \: transpose \: - 5 \: to \: left \: hand \: side \\ equation \: is \: \\ 2x - 3y + 5 = 0 \\ therefore \: \\ a = 2 ,\: b = - 3 ,\: c = 5 \\ \\ \\ (2) \: \: \: \: \: \: \: \: y = x + 3 \\ transpose \: y \: to \: right \: hand \: side \\ now \: equation \: is \: \\ x - y + 3 = 0 \\ therefore \\ a = 1 ,\: b = - 1 ,\: c = 3$

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