arrange the following in decreasing order of their bond angle ch4,
nh3, h2o, bcl3.
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Explanation:
we know that,
Bond Order is inversely proportional to Bond angle.
which means, when Bond Order increases Bond angle decreases.
Similarly, when Bond Order decreases Bond angle increases.
In this case,
The bond orders are respectively:
CH4 = 1
NH3 = 1
H2O = 1
Since, we get similar values we must look after Theory of VSEPR and arrange their bond angles.
Bond angle of CH4 = 109°28'.
Bond angle of NH3 < 109°28' (Due to 1 lone pair repulsion).
Bond angle of H2O << 109°28' (Very less because of 2 lone pair repulsion).
∴ CH4 > NH3 >H2O.
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