Question

arrange the following in increasing order of bond angle ch4,becl2,nh4

Answer 1

Explanation:

The given central elements carbon, beryllium ans nitrogen all belongs to the same period.

Geometry of $CH_{4}$ is tetrahedral. Therefore, its bond angle is equal to 109 degrees.

Whereas $BeCl_{2}$ is a linear compound and therefore bond angle of this compound is 180 degrees.

On the other hand, $NH_{4}$ has one lone pair of electron on nitrogen atom due to which there will occur repulsion between lone pair and bond pair. As a result, bonding atoms will come slightly closer to each other.

Hence, bond angle will decrease and it is less that 109 degrees.

Thus, we can conclude that bond angel of given compounds in increasing order is as follows.

                $NH_{4}$ < $CH_{4}$ < $BeCl_{2}$