Question

Arrange the following in the order of property indicated for each set:

(i) H2O, NH3, HCl, H2 (increasing magnitude of intermolecular forces)

(ii) O2, H2, He,N2 (ease of liquefaction)(Given critical temperature in K: 154.3, 33.2, 5.3, 126

respectively)

(iii) O2, He, CO2, CH4 (increasing value of van der Waal constant ‘a’)

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Answer 1

Answer:

Diamond is hard due to strong covalent bonds present in it. In a Graphite, carbon atoms are bounded together in a flat layers by an strong covalent bonds in a regular haxagon. These layers are held together by much wealer van der Wall's forces, therefore the crystals of graphite soft and slippery.

Answer 2

Diamond is hard due to strong covalent bonds present in it. In a Graphite, carbon atoms are bounded together in a flat layers by an strong covalent bonds in a regular haxagon. These layers are held together by much wealer van der Wall's forces, therefore the crystals of graphite soft and slippery.

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