Question

arrange the following rational number in ascending order​

Answer 1

Solution :-

The rational numbers are :-

$\sf{\dfrac{4}{3} , \dfrac{-5}{8} , \dfrac{7}{6} , \dfrac{-11}{12}}$

Firstly arrange them in like terms by taking its L.CM. as 24 ;

$\rightarrow{\sf{\dfrac{32, - 15, 28, - 22}{24}}}$

Now, differentiate them ;

$\rightarrow{\sf{\dfrac{32}{24} , \dfrac{-15}{24} , \dfrac{28}{24} , \dfrac{-22}{24}}}$

$\sf{The\ smallest\ is\ :- \dfrac{-22}{24}.}$

$\sf{The\ largest\ is\ :- \dfrac{32}{24}.}$

Now, arrange them in ascending order :-

$\sf{\dfrac{-22}{24} , \dfrac{-15}{24} , \dfrac{28}{24} , \dfrac{32}{24}}$

$\rightarrow{\sf{\dfrac{-11}{12} , \dfrac{-5}{8} , \dfrac{7}{6} , \dfrac{4}{3}.}}$

Hence, the ascending order is :-

$\rightarrow{\boxed{\boxed{\sf{\dfrac{-11}{12} < \dfrac{-5}{8} < \dfrac{7}{6} < \dfrac{4}{3}.}}}}$