Question

Arrange the fractions 1/3,2/5,3/4 and 1/6 in ascending order​

Answer 1

Given:-

• Arrange the fractions 1/3,2/5,3/4 and 1/6 in ascending order.

Solution:-

• $= > \frac{1}{3} - \frac{2}{5} - \frac{3}{4} - \frac{1}{6}$
• $\small\bold{L.C.M. of denominators}$

$2 |3 \: \: \: \: \: \: \: \: \: \: 5 \: \: \: \: \: \: \: \: \: \: \: 4 \: \: \: \: \: \: \: \: \: \: \: \: 6| \\ \\ \\ 3|3 \: \: \: \: \: \: \: \: \: \: \: 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3| \\ \\ \\ |1 \: \: \: \: \: \: \: \: \: \: \: \: 5 \: \: \: \: \: \: \: \: \: \: \: \: 2 \: \: \: \: \: \: \: \: \: \: \: 1| \\ \\ \\ = > 2 \times 3 \times 5 \times 2 \\ \\ \\ = > 60$

$\small\bold{Now, \: make \: the \: denominators \: same}$

• $= > \frac{1}{3} = \frac{1 \times 20}{3 \times 20} = \frac{20}{60} \\ \\ \\ = > \frac{2}{5} = \frac{2 \times12 }{5 \times 12} = \frac{24}{60} \\ \\ \\ = > \frac{3}{4} = \frac{3 \times 15}{4 \times 15} = \frac{45}{60} \\ \\ \\ = > \frac{1}{6} = \frac{1 \times 10}{6 \times 10} = \frac{10}{60}$

$\small\bold{So \: ascending \: order \: is}$

$\\ \\ \\ = > \frac{10}{60} < \frac{20}{60} < \frac{24}{60} < \frac{45}{60}$

$\\ \\ \\ = > \frac{1}{6} < \frac{1}{3} < \frac{2}{5} < \frac{3}{4}$

Explanation:-

• First of all to arrange fractions in any order with different denominators.

• The denominators must be changed to equivalent.

• For that we first found the l.c.m. and then made the denominators same as l.c.m. and also multiplied in numerators accordingly.

• And then arranged them from smaller to greater.

Hope it helped!