Question

Arrange the ions: Li2+, He+ and Be3+ in the increasing order of their ionic radii.

Answer 1

Your Answer:

The increasing order would be-
He+ < Li2+ < Be3+

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Answer 2

Order of increasing ionic radii is $Be^{3+}$ < $Li^{2+}$ < $He^{+}$

Explanation:

Isoelectronic species are defined as the molecules which have the same number of electrons.

Atomic number of Lithium is 3 and thus has 3 electrons. $Li^{2+}$ is formed by loss of 2 electrons and thus has 1 electron.

Atomic number of helium is 2 and thus has 2 electrons. $He^{+}$ is formed by loss of 1 electron and thus has 1 electron.

Atomic number of berrylium is 4 and thus has 4 electrons. $Be^{3+}$  is formed by loss of 3 electrons and thus has 1 electron.

As the number of electrons are same , the more is the nuclear charge i.e. the number of protons , more will the force of attraction towards the nuclei and thus smaller will be the radii and vice versa.

Thus, order of increasing ionic radii for the given ions is as follows.

$Be^{3+}$ < $Li^{2+}$ < $He^{+}$

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