arrange the number 1 2 3 4 5 and 6 so that the sum sum of the numbers on the vertical line is the same as the numbers in the horizontal line
Answers
Step-by-step explanation:
123456
654321
i think that this is the answer
May be ....
Multiple solutions/arrangements are possible
4
2 1 3 5
6
4
2 3 1 6
5
2
1 5 3 4
6
Assume that sum of horizontal line and vertical line = a
Then total sum = 2a ( Even number)
2a = 1 + 2 + 3 + 4 + 5 + 6 + k
k is number which is common to horizontal line and vertical line
=> 2a = 21 + k
Hence k must be 1 , 3 or 5
Case 1 : k = 1
=> 2a = 21 + 1
=> a = 11
4
2 1 3 5
6
Position of 4 and 6 can be interchanged
Positions of 2 , 3 and 5 can be interchanged
Case 2 : k = 3
=> 2a = 21 + 3
=> a = 12
4
2 3 1 6
5
Position of 4 and 5 can be interchanged
Positions of 2 , 1 and 6 can be interchanged
Case 3 : k = 5
=> 2a = 21 + 5
=> a = 13
2
1 5 3 4
6
Position of 2 and 6 can be interchanged
Positions of 1 , 3 and 4 can be interchanged
(Question missing figure which has been attached)
