Physics, asked by Thrived, 11 months ago

2. The electric field intensity required to just balance a liquid drop of 2 10kg  with charge 9.8 10μC  is

Answers

Answered by soumithkatta7

1

Answer:2.14x10^8 T

Explanation:

QxE=mg

9.810x10^-6xE=210x10

E=2100/(9.810x10^-6)

= 2.14x10^8 N/C

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