Math, asked by SehajbirKang2180, 1 year ago

Arrivals of customers at a telephone booth follow poisson distribution, with an average time of 10 minutes between one arrival and the next. the length of the phone call is assumed to be distributed exponentially with a mean of 3 minutes. find

a. the average number of persons waiting and making telephone calls

b. the average length of the queue that is formed from time to time.

c. probability that a customer arrive and find telephone booth is busy.

d. probability that a customer arrive and find telephone booth is empty.


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Answers

Answered by anshulkapoor143
42
Arrivals of customers at a telephone booth follow poisson distribution, with an average time of 10 minutes between one arrival and the next. the length of the phone call is assumed to be distributed exponentially with a mean of 3 minutes. find

a. the average number of persons waiting and making telephone calls

b. the average length of the queue that is formed from time to time.

c. probability that a customer arrive and find telephone booth is busy.

d. probability that a customer arrive and find telephone booth is empty.

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Answered by pavanadevassy
0

Answer:

(i) 0.43

(ii) 0.43

(iii) 0.3

(iv) 0.7

Step-by-step explanation:

a. the average number of persons waiting and making telephone calls

Average arrival rate = λ = 60/10 = 6 customers/hour

Average service rate = μ = 60/3 = 20 customers/hour

Utilization parameter = ρ = 6 /20 = 0.3

=/ − =6/20 −6 = 6/14= 0.43 customers

b. the average length of the queue that is formed from time to time.

Ls= ρ/1- ρ

= 0.3/1-0.3

= 0.43 customers

c. probability that a customer arrive and find telephone booth is busy.

      P (w > 0) = 1 – P0= 1 – (1 - λ / μ) = λ / μ= 0.10/0.33 = 0.3

d. probability that a customer arrive and find telephone booth is empty.

λ=0.1 per minute,

Service rate, μ=0.33 per minute

ρ= 0.1 / 0.33 =0.3

Probability that an arrival does not have to wait before service or probability that a system is idle,

p0 = 1- p = 1-0.3 =0.7

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