Question

Arthemetic progression additional problems for
sum of m and n terms of ap ratio is m square is to n square show that m and nth terms ratio is (2m-1):(2n-1)

Answer 1

ANSWER:-

GIVEN:-

                 Sm:Sn = m²: n²

SO......

       $\frac{\frac{m}{2}\left \(2a+(m-1)d)}{\frac{n}{2}(2a(n-1)d) }$$=\frac{m^{2} }{n^{2} }$

       $\frac{2a+(m-1)d}{2a+(n-1)d}=\frac{m^{2} }{n^{2} }$