Article A was sold at a profit of 50% and Article B was sold at a loss of 10%, which resulted to a profit of Rs. 65 for both. If the selling price of Article A was 250% of that of Article B, what was the cost of Article A?
Answers
Answer:
the answer is 250
Step-by-step explanation:
the sale price of a=250
the sp of b+a=350
the cp=285
the cp of b=111.11
the cp of a =173.89
sp of a= 173.89
173.89+89.91=250
174.89*50/100= ?
If the selling price of Article A was 250% of that of Article B, then the cost of Article A is Rs. 150.
Step-by-step explanation:
Let the cost price of article A be Rs. “x” and of article B be Rs. “y”.
Given that, Article A was sold at 50% profit while article B was sold at 10% loss.
Therefore,
S.P. of A = C.P. of A + Profit = x + (50/100)x = 1.5x
S.P. of B = C.P. of B - Loss = y – (10/100)y = 0.9y
Required Formula:
- S.P. – C.P. = Profit
After selling both the articles together, a profit of Rs. 65 was received.
Therefore, we can write the eq. as,
[S.P. of A + S.P. of B] – [C.P. of A + C.P. of B] = 65
⇒ [1.5x + 0.9y] – [x + y] = 65
⇒ 0.5x - 0.1y = 65 …….. (i)
Also given that,
S.P. of A is 250% of SP of B
i.e., SP of A = 2.5 * [SP of B]
⇒ 1.5x = 2.5 * [0.9y]
⇒ y = 0.67x …… (ii)
Substituting eq. (ii) in (i), we get
0.5x - 0.1(0.67y) = 65
⇒ 0.5x - 0.067x = 65
⇒ 0.433 X = 65
⇒ x = Rs. 150.11 ≈ Rs. 150
Thus, the cost price of article A is Rs. 150.
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